How do I extract the last part of a url?

English
#1

I have a column that looks like this:https://dqzrr9k4bjpzk.cloudfront.net/images/13505408/987611480.jpg
I only need this information which is the last par of the file name: 987611480.jpg
Thank you so much if you can help me solve this problem.

#2

You may use the FIND&REPLACE tool. Activate Regular Expressions.

Search: ^.*\/([:digit:]+\.jpg)$

Replace (all): $1

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