How can i do a matrix like this one?

[DJauri]

I’m able to do a matrix with brackets, but i need to place a row on top of the matrix, and outside the brackets.

best i can do so far is this:

size 15 P ~ ~ ~ = ~ ~ ~ ~ ~size 12 stack{ ~ #i ~# j ~ # k ~  # l ~  # m ~} 
left (
stack{ ~ i#  .06  # .1 # .16# .26 # .42 } 
~~ 
stack{~ j#.42  #.06 # .1# .16 # .26} 
~~
stack{ ~ k #.26 # .42 # .06 # .1 # .16} 
~~
stack{~ l #.16  # .26 # .42# .06 # .1} 
~~
stack{~ m #.1  # .16 # .26# .42 # .06} 
right  ) 

thank you!

(formatting editing by ajlittoz – hoping not having changed the meaning)

[keme]

Attach the brackets “outside” the matrix. Use some phantoms for sizing of brackets and positioning the matrix within brackets:

 P^2 = left none stack {rain # nice # snow } right ( 
 matrix 
 {rain # nice # snow ##
 .438 # .188 # .375 ## 
 .375 # .250 # .375 ## 
 .375 # .188 # .438 ##
 phantom 1 #phantom 1 # phantom 1 } 
 left ) stack {phantom rain # phantom nice # phantom snow } right none 

The phantom line below may give unwanted spacing below your formula. Adjustment should be possible.

[EarnestAl]

Elegant and readable. Wow!

[DJauri]

agree, thank you!

[EarnestAl]

@DJauri if the answer solves your problem then please click on the tick beside keme’s answer to show others it has been solved. Cheers, Al

[keme]

Missed the fact that target data is a bit different from the sample display (which I suspect that @DJauri manages nicely) and also that phantom can be used on blocks, not only on single items, which improves the suggested solution a bit:

 size 15 

 P ~ ~ ~ = ~ ~ ~ ~ ~

 size 12 

 left none 
 stack{ i ~ # j ~ # k ~ # l ~ # m ~} 
 right ( 

 matrix { 
 i #j #k #l #m ##
 .06 # .42 #.23 #.16 #.1 ##
 .1 #.06 #.42 #.23 #.16 ##
 .16 #.1 #.06 #.42 #.26 ##
 .26 #.16 #.1 #.06 #.42 ##
 .42 #.26 #.16 #.1 #.06 ##
 ""  #"" # ""# "" # phantom X
  }

 left ) 
 phantom stack{ i ~ # j ~ # k ~ # l ~ # m ~} 
 right none

[Lupp]

I don’t know a systematic way to align the headers with columns of an independent structure below.
A very crude tinkerer’s approach, that may be acceptable for a single case or two:

left none matrix{"                       "i # "     "j # "     "k # "     "l # "    "m}  right none
newline
size 15P ~ ~ ~ = ~ ~  ~ ~size 12 stack{ i ~# j ~ # k ~ # l ~ # m ~}
left ( stack{   .06 # .1 # .16# .26 # .42 } ~~ stack{~ .42 #.06 # .1# .16 # .26} ~~ 
stack{ ~ .26 # .42 # .06 # .1 # .16} ~~ stack{~ .16 # .26 # .42# .06 # .1} ~~ 
stack{~ .1 # .16 # .26# .42 # .06} "  " right )

[DJauri]

it ceretainly does the job! thank you!

[LeroyG]

Another aproximation:

size 15P ~  = ~ ~size 12 stack { ~ # i ~# j ~ # k ~ # l ~ # m ~}
binom { alignc ~ i ~~~ j ~~~  k ~~~ l ~~~  m } 
{ alignc left (  {  stack {.06 # .1 # .16# .26 # .42 } }
~ { stack {.42 # .06 # .1# .16 # .26 }} 
~ { stack {.26 # .42 # .06 # .1 # .16} }
~ { stack {.16 # .26 # .42# .06 # .1} }
~ { stack { .1 # .16 # .26# .42 # .06 } }right ) }

p is not vertically well aligned.

Made with LibreOffice 6.4.7.2 (x86); OS: Windows 6.1.

---

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[DJauri]

está genial así, gracias!

[ajlittoz]

@LeroyG was nearly at it.

You should consider that the right-hand side is made of a “comment” line and the matrix. This is what is meant by the stack function. To have the left-hand side correctly aligned, i.e. P =vertically centered relative to the matrix, we must also have two elements stacked over each other.

My formula is then:

stack { size 12 ~ # size 15 P ~  "="}             -- left-hand side
                                                  -- and below, right-hand side unchanged
~ ~size 12 stack { ~ # i ~# j ~ # k ~ # l ~ # m ~}
binom { alignc ~ i ~~~ j ~~~  k ~~~ l ~~~  m } 
{ alignc left (  {  stack {.06 # .1 # .16# .26 # .42 } }
~ { stack {.42 # .06 # .1# .16 # .26 }} 
~ { stack {.26 # .42 # .06 # .1 # .16} }
~ { stack {.16 # .26 # .42# .06 # .1} }
~ { stack { .1 # .16 # .26# .42 # .06 } }right ) }

with result:

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[DJauri]

very nice, thx!

[DJauri]

also thanks for the format change, as you may guess, i’m quite new here!