Where is the "eraser tool" in libraDraw?

The little eraser tool as in MSPaint. Not “cut” but just erase IE: erase the string hanging from a Red Balloon.
Had another question anwered a few days ago. Thanks!

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Draw is not a paint application: its goal is not to paint patches of color on a frame (a bitmap) but to build a set of vectorial shapes with specific updatable properties (position, label, size, color, relation to each other, …).

Consequently, the notion of an eraser is meaningless.

However, every item is updatable. First, select it either with a click with the arrow tool or drag a rectangle with the same tool around the object(s). Then, change the desired properties with the menus (or right click). A basic property change is available with the Delete or Backspace key to delete the object.

Modifying text is a bit trickier because text is a “deeper” attribute of an object. If you proceed as suggested in the preceding paragraph, you may destroy the object instead of the text. When dealing with text only, double click the text to select only the characters, not the hosting object. Then, Delete or Backspace will operate only on the string without harming the object.

If this answer helped you, please accept it by clicking the check mark to the left and, karma permitting, upvote it. If this is what you expected, close the question, that will help other people with the same question.

ajlittoz, your answer is disrespectful and unhelpful. Not everyone using this suite is a computer professional so of course we do not know correct terminology. However, if one wants to remove a little of a freeform line, “erase” is the logical term to use.

If one does not want to delete an object–just modify it slightly, nor wants to modify text, your answer is worthless.

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I had not the feeling of being computer professional.

If you want to modify an object, first select it. Little black square patches appear on “important” points of the shape (called “handles”). Grab one of them and drag it to change the attribute related to this handle (position of point, size of a side, angle, …).

+1 because I thought your answer was quite good. Thank you.

@EasyTrieve you’re welcome

ajlittoz, your answer was spot on! thanks.